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If p ∈ (A×C)∩(B ×C), then p ∈ A×C and p ∈ B ×C, so p = (x,y) with x ∈ A and y ∈ C, and x ∈ B and y ∈ C This implies x ∈ A∩B and y ∈ C, so p = (x,y) ∈ (A∩B)×C This proves (A×C)∩(B ×C) ⊆ (A∩B)×C Together the two inclusions prove the claimed equality 1 2. Disclaimer All content on this website, including dictionary, thesaurus, literature, geography, and other reference data is for informational purposes only. Report_of_the_Attorney_General'S=eﾀS=eﾀBOOKMOBI ・ ・06 7 > E K P V ^ g o1 v@ }ｭ ・ ・ 都 嗔 ｡・"ｩw$ｰ・&ｷｲ(ｿ・*ﾇc,ﾏKﾗh0ﾝｶ2胄4・6 8 ・ ・ ｮ・ ・ ｵz ・ ｹ・ ・ ｾj ・ ﾃC ・ ﾆL ・ ﾆO ・ ﾇG ・ ﾐ ・ ﾑ・ ・ ﾒ・ ・ ﾕﾟ ・ ﾖﾇ ・ ﾗ・ ﾗｫ.
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