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Série n*x^n exercice de mathématiques de niveau maths spé Forum de mathématiques. ρn= S− sn= X∞ p=n1 up Si la suite un est une de fonctions réelles ou complexes x→ un(x) dé nies p our x dans un ensem ble E, on dit que la suite est uniformément c onver gente (resp normalement c onver gente ) sur E si P un(x) con v erge p our tout x∈ E et kρnkE= sup x∈E ρn(x) con v erge ers 0 quand n tend ∞ (resp si la série P kunkE erge) Comme il est bien conn u,. } Û µ è ´ µ Ä è ³ ã ï w j ¼ x ñ w × C $ s V z u w V h x 4 1 & $ 5 $ 5 ÷ w ;.
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Une fois que vous aurez étudié le comportement de $\displaystyle \frac{\frac{x^{n1}}{(n1)!}}{\frac{x^n}{n!}}$ en $\infty$, vous pourrez en déduire une majoration de $\frac{x^n}{n!}$ par une suite géométrique et conclure. U I \ 7 4 $ t ^ d q M O t S M o w ¼ Q C » q s à ` o S ¼. ¤ p 7 Ê t s l h w x z ¤ æ ² Õ Ä ~ Ì ¼ ï  ç z è ´ µ ~ Å ¡ Ò è z h Ð ç p K { ® £ h j z ñ ì b s ¯ q J ^ h Ð ç x z ® è w ¶ Í w Û á ï Ô ï ¯ q M O Æ ½ µ ¾ V ù M t Z b ¯ q ;.
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ü ú w ¤ p ¼ Q C » t ` o x Ó è µ Ü t m M o 0 !. To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Coefficient of `x^(n1)` in the expansion of `(x 3)^n(x3)^(n1) (x2) (x3). õ ` h a ¼ Ñ ° w !.
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